Answer:
2.4681 m/s
Explanation:
[tex]m_1[/tex] = Mass of cannon ball = 29 kg
[tex]m_2[/tex] = Mass of performer = 65 kg
[tex]u_1[/tex] = Initial Velocity of cannon ball = 8 m/s
[tex]u_2[/tex] = Initial Velocity of performer = 0 m/s
v = Velocity of combined mass
As the linear momentum of the system conserved
[tex]m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow v=\frac{m_1u_1 + m_2u_2}{m_1 + m_2}\\\Rightarrow v=\frac{29\times 8 + 65\times 0}{29 + 65}\\\Rightarrow v=2.4681\ m/s[/tex]
The recoil velocity is 2.4681 m/s