Question

Suppose we have a 12.2litre sample containing 0.50M of oxygen at 25°c.If all of this oxygen(o2) is converted to ozone at the same temperature and pressure.What will be the volume of ozone?

Answer 1

Answer:

V2 = 8.2 L

Explanation:

Given data:

Molarity of oxygen = 0.50 M

Volume = 12.2 L

Volume of ozone = ?

Solution:

Number of moles of oxygen = molarity × volume

Number of moles = 0.50 M ×12.2 L

Number of moles = 6.1 mol

Chemical equation:

3O₂   →   2O₃

Moler ratio:

O₂   :   O₃

3     :    2

6.1   :   2/3×6.1 = 4.1 mol

According to Avogadro law:

V1/n1 = V2/n2

V2 = V1n2/n1

V2 = 12.2 L × 4.1 mol/ 6.1 mol

V2 = 50.02 L. mol / 6.1 mol

V2 = 8.2 L