Respuesta :
Answer:v=21.10 m/s
Step-by-step explanation:
Given
Radius of Turn r=370 m
inclination of bank [tex]\theta =7^{\circ}[/tex]
From diagram Resolving Normal Reaction R
[tex]R\cos \theta =mg[/tex]------1
[tex]R\sin \theta =\frac{mv^2}{r}[/tex]-----2
Divide 1 and 2 we get
[tex]\tan \theta =\frac{v^2}{rg}[/tex]
[tex]\tan (7)=\frac{v^2}{rg}[/tex]
[tex]v^2=\tan (7)\times 370\times 9.8[/tex]
[tex]v^2=445.21[/tex]
[tex]v=21.10 m/s[/tex]
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The speed limit so that a car turns successfully will be 21.11m/s
It is given that
The radius of Turn 'r'=370 m
The inclination of bank 'α'= 7 degree
We have to calculate, the speed limit you post so that a car traveling at that speed negotiates the turn successfully even when the road is wet and slick.
What is the formula for the banking of roads?
[tex]tan \alpha =\frac{v^{2} }{gr}[/tex], when the road is smooth
Where α is bank angle
v is the speed for a successful turn
Put the given values in the above equation.
tan 7 = v²/(9.81*370)
v= 21.111 m/s
Hence, The speed limit so that a car turns successfully will be 21.11m/s
To get more about banking of a road refer to the link,
https://brainly.com/question/14449938