Question

A simple pendulum having a length of 2.61 m and a mass of 3.93 kg undergoes simple harmonic motion when given an initial speed of 2.45 m/s at its equilibrium position. Determine its period. The acceleration due to gravity is 9.8 m/s 2 . Answer in units of s.

Answer 1

Answer:

T=3.24s

Explanation:

Period of a simple pendulum is given by:

$T=2*\pi*\sqrt{L/g}$

$T=2*\pi*\sqrt{2.61/9.8}$

$T=3.24s$

As you can see, it doesn't depend on the mass of the object, nor its speed.