Answer:
T=23.713 C
Explanation:
Knowing the bat lengthens by 0.000172m and the initial temperature 12.4 C to find the final temperature use the equation of length:
ΔL = α * Lo * ΔT
α=23x10^-6 C Aluminum constant
T = To + ΔT
ΔT = ΔL / α * Lo
T = To + ΔL / α * Lo
T = 12.4 C + 0.172x10^-3m / 23x10^-6C * 0.661m
T=23.713 C
