Question

Question 5 A 8.00L tank at 0.6°C is filled with 8.79g of sulfur hexafluoride gas and 19.5g of carbon dioxide gas. You can assume both gases behave as ideal gases under these conditions. Calculate the mole fraction of each gas. Be sure each of your answer entries has the correct number of significant digits.

Answer 1

Answer:

Mole fraction SF₆: 0.119

Mole fraction CO₂: 0.881

Explanation:

Mole fraction: Moles of gas / Total moles

Molar mass SF6: 146.0 g/m

Molar mass CO2: 44.0 g/m

Moles : mass / molar mass

Moles SF₆ : 8.79 g/ 146.0 g/m = 0.060 moles

Moles CO₂: 19.5 g / 44.0 g/m = 0.443 moles

Total moles: 0.060 moles + 0.443 moles = 0.503 moles

Mole fraction SF₆:  0.060 moles/0.503 moles = 0.119

Mole fraction CO₂: 0.443 moles/0.503 moles = 0.881

Sum of mole fraction every gas = 1