plz answer :)
Anita sells stuffed bunnies and puppies to a toy store. She sells each bunny for $8.00 and each puppy for $10.00. This week, Anita wants to sell more than 30 stuffed animals and needs to earn a minimum of $450. Which system of inequalities can Anita use to determine the number of stuffed bunnies, x, and stuffed puppies, y, that she can sell to meet her goals?
A. x + y > 30 8x + 10y ≥ 450
B. x + y > 30 8x + 10y ≤ 450
C. x + y < 30 8x + 10y ≥ 450
D. x + y < 30 8x + 10y ≤ 450

When 2 or more expressions are not equal and they have greater than(>), greater than or equal to(≥), less than(<), or less than or equal to(≤) sign in between them, then it is called an inequality.

How to find which system of inequalities can Anita use to determine the number of stuffed bunnies that she can sell to meet her goals ?

According to the problem,

Price of each bunny = $8.00
Price of each puppy = $10.00

Number of stuffed bunnies = x and number of stuffed puppies = y

∴ 8x + 10y will give the total money that Anita will earn.

Now, minimum earning Anita wants = $450

∴ we can say 8x + 10y ≥ 450

Again , according to the problem,

Anita wants to sell more than 30 stuffed animals

∴ x + y ≥ 30

These inequalities clearly matches with option A

So, option A is correct

Find out more about 'Inequalities' here: https://brainly.com/question/24372553

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