Answer:
μ= 3.2 minutes
σ=1.6 minutes
a ) Find the probability that their mean time at the teller's counter is at most 2.7 minutes.
[tex]P(x \leq 2.7)[/tex]
[tex]Z=\frac{x-\mu}{\sigma}[/tex]
[tex]Z=\frac{2.7-3.2}{1.6}[/tex]
[tex]Z=-0.3125[/tex]
Refer the z table for p value
p value = 0.3783
Hence the probability that their mean time at the teller's counter is at most 2.7 minutes is 0.3783
b)Find the probability that their mean time at the teller's counter more than 3.5 minutes.
[tex]P(x >3.5)[/tex]
[tex]Z=\frac{x-\mu}{\sigma}[/tex]
[tex]Z=\frac{3.5-3.2}{1.6}[/tex]
[tex]Z=0.1875[/tex]
Refer the z table for p value
p value = 0.5714
P(x>3.5)=1-P(x<3.5)=1-0.5714=0.4286
Hence the probability that their mean time at the teller's counter more than 3.5 minutes is 0.4286
c)Find the probability that their mean time at the teller's counter at least 3.2 minutes but less than 3.4 minutes.
[tex]P(3.2 \leq x\leq 3.5)[/tex]
[tex]Z=\frac{x-\mu}{\sigma}[/tex]
[tex]Z=\frac{3.2-3.2}{1.6}[/tex]
[tex]Z=0[/tex]
Refer the z table for p value
p value = 0.5
[tex]Z=\frac{x-\mu}{\sigma}[/tex]
[tex]Z=\frac{3.5-3.2}{1.6}[/tex]
[tex]Z=0.1875[/tex]
Refer the z table for p value
p value = 0.5714
[tex]P(3.2 \leq x\leq 3.5)=P(x<3.5)-P(x<3.2)=0.5714-0.5=0.0714[/tex]
Hence the probability that their mean time at the teller's counter at least 3.2 minutes but less than 3.4 minutes is 0.0714