Question

There is a spinner with 13 equal areas, numbered 1 through 13. If the spinner is spun one time, what is the probability that the result is a multiple of 3 and a multiple of 4?

Answer 1

Answer:

The probability that the result is a multiple of 3 and a multiple of 4 is

⇒ $\frac{1}{13}$

Step-by-step explanation:

The spinner is numbered from 1 to 13.

When the spinner is spun once, the possible outcomes are

{1,2,3,4,5,6,7,8,9,10,11,12,13}

Desired outcome is a multiple of 3 and a multiple of 4. So, the number should be divisible by 3 as well as 4.

List of multiples under the possible outcomes:

3⇒ 3,6,9,12

4⇒ 4,8,12

We see that the least common multiple is 12 which is an outcome.

∴ Number of desired outcomes =1

Probability of desired outcome = $\frac{number\ of\ desired\ outcomes}{Total\ number\ of\ outcomes}$

⇒ $\frac{1}{13}$

Answer 2

The probability that the result is a multiple of 3 and a multiple of 4 is 1/13

The multiples of 3 and 4 from number 1 to 13 is 12

This means that there is one multiple of 3 and 4 from number 1 to 13 is 12

So, the probability that the result is a multiple of 3 and a multiple of 4 is 1/13

Read more about probability at:

https://brainly.com/question/25870256