Question

Giovanni purchased 25tickets to an airshow. the cost of an adult's ticket is $14 and the child's ticket is $8. if the total cost was $320, find the number of adult tickets and number of child purchased.

Answer 1

Giovanni purchased 20 adult tickets and 5 child's tickets.

Step-by-step explanation:

Let,

x = Adult tickets

y = Child's tickets

According to given statement;

x+y=25 Eqn 1

One adult ticket costs $14 and one child ticket costs $8, therefore,

14x+8y=320 Eqn 2

$Multiplying\ Eqn\ 1\ by\ 8\\8(x+y=25)\\8x+8y=200\ Eqn\ 3\\Subtracting\ Eqn\ 3\ from\ Eqn\ 2\\(14x+8y)-(8x+8y)=320-200\\14x+8y-8x-8y=120\\6x=120\\Dividing\ both\ sides\ by\ 6\\\frac{6x}{6}=\frac{120}{6}\\x=20$

Putting value of x in Eqn 1;

$20+y=25\\y=25-20\\y=5$

Giovanni purchased 20 adult tickets and 5 child's tickets.

Keywords: Linear equations, Addition

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