Answer:
Work done, W = 5534.53 J
Explanation:
It is given that,
Force acting on the piano, F = 6157 N
It is pushed up a distance of 2.41 m friction less plank.
Let W is the work done in sliding the piano up the plank at a slow constant rate. It is given by :
[tex]W=Fd\ sin\theta[/tex]
Since, [tex]F=F\ sin\theta[/tex] (in vertical direction)
[tex]W=6157\times 2.41\ sin(21.9)[/tex]
W = 5534.53 J
So, the work done in sliding the piano up the plank is 5534.53 J. Hence, this is the required solution.