What is the formula when the halogen from 3rd principal energy level combines with you alkaline earth metal from the 4th energy level?

Respuesta :

Answer: [tex]CaCl_2[/tex]

Explanation:

Principle Quantum Numbers : It describes the size of the orbital and the energy level. It is represented by n. Where, n = 1,2,3,4....

Halogen with n=3 is chlorine.

Alkaline earth metal with n = 4 is calcium.

An ionic bond is formed when an element completely transfers its valence electron to another element.

Electronic configuration of calcium

[tex][Ca]=1s^22s^22p^63s^23p^64s^2[/tex]

calcium atom will loose one electron to gain noble gas configuration and form calcium cation with +2 charge.

[tex][Ca^{2+}]=1s^22s^22p^63s^23p^6[/tex]

Electronic configuration of chlorine:

[tex][Cl]=1s^22s^22p^63s^23p^5[/tex]

Chlorine atom will gain one electron to gain noble gas configuration and form chloride ion with -1 charge.

[tex][Cl^-]=1s^22s^22p^63s^23p^6[/tex]

Here [tex]Ca^{2+}[/tex] cation and chloride [tex]Cl^{-}[/tex] anion combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral [tex]CaCl_2[/tex].

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