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Your new TV screen has a width that is 4 inches longer than its height. If the screen's diagonal measurement is 20 inches, find the height.

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Answer:

So the height is 12

Step-by-step explanation:

Let W be the width

Let W- 4 be the height

W2 +(W-4)2 = 400

So: W2 -4W-192 =0

One uses the quadratic solution:

W = (4 + (16 + 4*192).5)/2 = 16

Your new TV screen has a width that is 4 inches longer than its height. If the screen's diagonal measurement is 20 inches, then the height will be 12 inches.

What is a quadratic equation?

A quadratic equation is the second-order degree algebraic expression in a variable.

The standard form of this expression is  ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

Let W be the width and W- 4 be the height

Then we have;

W^2 +(W-4)2 = 400

So:

W^2 -4W-192 =0

The quadratic solution will be

W = (4 + (16 + 4*192).5)/2

W = 16

The height = w - 4 = 16 - 4 = 12

Hence, Your new TV screen has a width that is 4 inches longer than its height. If the screen's diagonal measurement is 20 inches, then the height will be 12 inches.

Learn more about quadratic equations;

brainly.com/question/13197897

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