Question

If 9.5 atms of pressure were increased to 25 atms of pressure, what would be the final volume
of a gas that originally occupied a space of 95 L?

Answer 1

Answer:

The final volume of the gas is 36.1 L.

Explanation:

Given:

Initial pressure of the gas is, $P_1=9.5\ atm$

Final pressure of the gas is, $P_2=25\ atm$

Initial volume of the gas is, $V_1=95\ L$

Final volume of the gas is, $V_2=?$

Here, we shall use Boyle's Law which states that for a process under constant temperature, the pressure of the gas changes inversely with the change in volume.

Here, the pressure is increased. So, the volume of the gas is decreased.

Therefore, as per Boyle's Law:

$P_1V_1=P_2V_2\\9.5\times 95=25V_2\\902.5=25V_2\\V_2=\frac{902.5}{25}\\V_2=36.1\ L$

So, the final volume of the gas is 36.1 L.