Question

While setting up a fireworks display, you have a tool at the top of the

building and need to drop it to a coworker below.

a. How long will it take the tool to fall to the ground? (Hint: use the first

equation that you were given above, h(t)=-16t^2+h0


h=10 feet


Could someone explain how to work this out rather than just giving the answer?

Answer 1

Answer:

0.79 sec

Step-by-step explanation:

Given there is a tool at the top of the building which is dropped by a worker and it follows the following equation at every instant of time .

$h(t)=-16t^{2} +h_{0}$

where $h_{0} =10 feet$

We know that this height is measured from the base of the building which means that when the tool reaches the bottom of the building it has h = 0 feet.

Let this be done at time t

h(t) = 0

$-16t^{2} +10=0$

$t^{2} =\frac{10}{16}$

$t=\frac{\sqrt{10} }{4}$

t = 0.79 sec

Therefore the total time taken by the tool to reach the bottom of the building is 0.79 sec.