Answer:
D. No, because [tex]P(A|B)=0.22[/tex] and the [tex]P(A) = 0.53[/tex] are not equal.
Step-by-step explanation:
Given:
Probability of doing yard work is, [tex]P(A)=53\%=0.53[/tex]
Probability of raining, [tex]P(B)=68\%=0.68[/tex]
Probability of doing yard work and it raining is, [tex]P(A\cap B)=15\%=0.15[/tex]
Now, two events A and B are independent if,
[tex]P(A|B)=P(A);P(B|A)=P(B)[/tex]
Conditional probability of event A given that B has occurred is given as:
[tex]P(A|B)=\frac{P(A\cap B}{P(B)}\\P(A|B)=\frac{0.15}{0.68}=0.22[/tex]
So, [tex]P(A|B)=0.22\ and\ P(A)=0.53[/tex]
Since, [tex]P(A|B)\ne P(A)[/tex], A and B are not independent events.