The equation of line through the given points is:
[tex]y=\frac{5}{9}x+\frac{40}{9}[/tex]
Step-by-step explanation:
Given points are:
(-8,0) = (x1,y1)
(1,5) = (x2,y2)
The slope-intercept form of line is:
[tex]y=mx+b[/tex]
We have to find the slope first
[tex]m=\frac{y_2-y_1}{x_2-x_1}\\m= \frac{5-0}{1-(-8)}\\m=\frac{5}{1+8}\\m=\frac{5}{9}[/tex]
Putting the value of slope
[tex]y=\frac{5}{9}x+b[/tex]
To find the value of y-intercept, we'll put the point (1,5) in the equation
[tex]5=\frac{5}{9}(1)+b\\5=\frac{5}{9}+b\\b=5-\frac{5}{9}\\b=\frac{45-5}{9}\\b=\frac{40}{9}[/tex]
Putting the values of b and m in the equation
[tex]y=\frac{5}{9}x+\frac{40}{9}[/tex]
The equation of line through the given points is:
[tex]y=\frac{5}{9}x+\frac{40}{9}[/tex]
Keywords: Equation of line, slope-intercept form
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