Question

The point-slope form of the equation of the line that passes through (4, -3) and (12, 1) is y-1= 2(x - 12). What is the
standard form of the equation for this line?
OX - 4y=8
O x-4y=2
4x - y = 8
4x - y = 2
co search
д в ее 9

Answer 1

Answer:

$x - 2y = 10$

Step-by-step explanation:

We were given the point-slope form equation of the line that passes through (4, -3) and (12, 1) as

$y - 1 = \frac{1}{2}(x - 12)$

To find the standard form, we expand and rewrite the equation in the form:

$ax + by = c$

where a, b, and c are constants.

$\implies \: y - 1 = \frac{1}{2} x - 6$

This implies that:

$- 1 + 6 = \frac{1}{2}x - y$

$\implies \: 5 = \frac{1}{2}x - y$

Multiply through by 2 to get:

$10 = x - 2y$

We can rewrite to get:

$x - 2y = 10$