Answer:
The dimensions are 18 * 18 * 36in
Step-by-step explanation:
Let the lengths of the square ends be x in and the length be y in.
Then the maximum length + girth
= 4x + y = 108in
The volume V = x^2y.
From the first equation:
y = 108 - 4x
so V = x^2(108 - 4x)
= 108x^2 - 4x^3
Finding the derivative:
V' = 216x - 12x^2 = 0 ( for a maximum volume).
12x( 18 - x) = 0
x = 18
So the value for x for a maximum volume = 18 in
This gives y = 108 - 4(18) = 36 in.