Given f(x) and g(x) = f(k⋅x), use the graph to determine the value of k.

Two lines labeled f of x and g of x. Line f of x passes through points negative 4, 0 and 0, 4. Line g of x passes through points negative 2, 0 and 0, 4.

-2
-1/5
1/5
2

Given fx and gx fkx use the graph to determine the value of k Two lines labeled f of x and g of x Line f of x passes through points negative 4 0 and 0 4 Line g class=

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Answer:

k=2

Step-by-step explanation:

Clearly both the functions are straight lines

the equation of  straight line passing through the two points (a , b) and (c , d) is [tex]y-b=\frac{d-b}{c-a}(x-a)[/tex]

Now f(x) passes through (-4 , 0) and (0 , 4)

the equation is [tex]y-0=\frac{4-0}{0-(-4)}(x-(-4))[/tex]

y=x+4

Now g(x) passes through (-2 , 0) and (0 , 4)

the equation is [tex]y-0=\frac{4-0}{0-(-2)}(x-(-2))[/tex]

y=2x+4

here f(x)=x+4 and g(x)=2x+4

clearly g(x)=f(2x)

therefore k=2

Answer:

K = 2

Step-by-step explanation:

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