Question

Calculate the conductance of a conduit whose cross-sectional area is 2.0 cm2 and whose length is 9.0 cm if its conductivity is 0.70 ohm-1cm-l. G = _____ ohm-1 0.32 0.31 0.16 6.4

Answer 1

Answer:

$0.16 ohm^{-1}$

Explanation:

Cell constant, k is given by, $k={L}{A}$ where L is length and A is area. Substituting A for $2 cm^{2}$ and L for 9 cm we obtain

$k=\frac {9}{2}=4.5 cm^{-1}$

Conductance, C is given by dividing conductivity by cell constant hence

$C=\frac {R}{k}$

Substituting 0.7 for R we obtain

$C=\frac {0.7}{4.5}= 0.155555556 ohm^{-1}\approx 0.16 ohm^{-1}$

Answer 2

Answer:

G = 0.16

Explanation:

G=0.7/(9/2)

G=0.16