Question

a student is given a reading list of ten books from which he must select two for an outside reading requirement. in how many ways can he make his selection

Answer 1

Answer:

The ways in which he can make selection = $10\times 9 =90$

Step-by-step explanation:

Student is having a list of $10$ books.

Assuming that the student can't read the same book twice.

The student has $2$ choices to make for an outside reading requirement,for his 1st choice, he had $10$ books to choose from; for his 2nd, he has $9$ books left to choose from therefore the total permutations of his choices are $=10\times 9 =90$

So the total ways in which the student can make his selection = $90$

Answer 2

Answer:

45

Step-by-step explanation:

Acellus suckz

Basically you have to multiply 10x9 for the numerator, and the denominator is 2x1, so as you know 10x9 is 90, divide that by 2x1 (basically just 2) and you get 45 :)