Answer: copper
Explanation:
Given :
[tex]heat_{aluminium}=heat_{copper}[/tex]
[tex]m_{Al}=m_{Cu}[/tex]
[tex]c_{Al}[/tex] > [tex]c_{Cu}[/tex]
As we know that,
[tex]Q=m\times c\times \Delta T[/tex]
where,
Q = heat absorbed or released
[tex]m[/tex] = mass of substance
[tex]\Delta T[/tex] = change in temperature
[tex]c[/tex] = specific heat of substance
[tex]m_{Al}\times c_{Al}\times \Delta T{Al}=m_{Cu}\times c_{Cu}\times \Delta T{Cu}[/tex]
[tex]c_{Al}\times \Delta T{Al}=c_{Cu}\times \Delta T{Cu}[/tex]
Given the heat absorbed is same, As specific heat capacity of copper is less than that of aluminium, the increase in temperature should be faster for copper as compared to that of aluminium.