Answer:
Step-by-step explanation:
Given that an exit poll of 1000 randomly selected voters found that 515 favored measure A.
Sample proportion p = [tex]\frac{515}{1000} =0.515[/tex]
[tex]q=1-0.515 =0.485\\n =1000\\SE = \sqrt{\frac{pq}{n} } \\=0.158\\[/tex]
Margin of error 99% = 2.58*SE
=[tex]2.58*0.0158\\=0.0408[/tex]
99% confidence interval =[tex](0.515-0.0408, 0.515+0.0408)\\= (0.474, 0.556)[/tex]
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[tex]H_0: p =0.5\\H_a: p >0.5\\[/tex]
(Right tailed test)
STd error = [tex]\sqrt{\frac{0.5*0.5}{1000} } \\=0.0158[/tex]
Test statistic Z = p diff/std error =[tex]\frac{0.015}{0.0158} \\\\=0.9487[/tex]
p value = 0.1714