Answer:
Q16.
Quadrant II is (- , +)
I choose the point (-1, 1) and the slope 1.
Substitute point and slope into the formula to find b.
y = mx + b
1 = (1)(-1) + b
b = 2
The equation is y = x + 2
Q15.
The slope is represented by the m value in y=mx+b. Choose a random negative value for m. I will make b 0 so I don't need to write it.
y= -x (slope is negative 1)
Q14.
m = 5; (-6,1)
Sub m and point into y=mx+b; isolate for b.
y=mx+b
1=5(-6)+b
1 = -30 + b
b = 31
Sub b=31 and m=5 into equation of a line
The equation is y = 5x + 31
Q13.
Find slope:
Choose points (0, 8) and (1, 10)
m = (y2-y1)/(x2-x1) = (10-8)/(1-0) = 2/1 = 2
Find b by substituting slope and point (0,8) into equation of a line
y=mx+b
8=2(0)+b
8 = 2 + b
b = 6
Sub b=6 and m=2 into y=mx+b
The equation of the line is y=2x+6
Q12.
Find slope between (5,2) and (6,4)
m = (y2-y1)/(x2-x1) = (4-2)/(6-5) = 2/1 = 2
Find b by substituting slope and point (5,2) into equation of a line
y=mx+b
2 = 2(5) + b
2 = 10 + b
b = -8
Sub b= -8 and m=2 to find equation
The equation of the line is y=2x-8
Q11.
Sub m= -4 and point (5,9) into the equation of a line, isolate b
y=mx+b
9 = -4(5) + b
9 = -20 + b
b = 29
Sub b=29 and m= -4 into the equation of a line
The equation of a line is y = -4x + 29
