Question

The sum of two consecutive integers is 123 what’s is the smallest of the two integers

Answer 1

The smallest of two integers is 61

Step-by-step explanation:

Let x be the smaller integer

Then the next integer will be:

x+1

According to given statement that the sum of both is 123

$x+ (x+1) = 123\\x+x+1=123\\2x+1=123$

Subtracting 1 from both sides

$2x+1-1=123-1\\2x=122$

Dividing both sides by 2

$\frac{2x}{2}=\frac{122}{2}\\x=61$

The smallest of two integers is 61

Keywords: Linear equations, Variables

Learn more about linear equations at:

• brainly.com/question/2670657
• brainly.com/question/2821386

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Answer 2

The smallest of the two integers is 61

Represent the consecutive numbers with x and y, where x is the smallest of the two numbers.

So, we have the following system of equations

x + y =123

y = x + 1

Substitute x + 1 for x in x + y =123

x + x + 1 =123

Subtract 1 from both sides

x + x =122

Evaluate the like terms

2x = 122

Divide both sides by 2

x = 61

Hence, the smallest of the two integers is 61

Read more about consecutive numbers at:

https://brainly.com/question/10853762