The Nelson Company makes the machines that automatically dispense soft drinks into cups. Many national fast food chains such as McDonald's and Burger King use these machines. A study by the company shows that the actual volume of soft drink that goes into a 16-ounce cup per fill can be approximated by a normal model with mean 16 ounces and standard deviation 0.31 ounces. A new 16-ounce cup that is being considered for use actually holds 16.62 ounces of drink.a. What is the probability that a new cup will overflow when filled by the automatic dispenser? .0228b. The company wishes to adjust the dispenser so that the probability that a new cup will overflow is .006. At what value should the mean amount dispensed by the machine be set to satisfy this wish? [ looking for help with this answer ] ounces. (Use 2 decimal places in your answer and use 0.31 ounces for the standard deviation).

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Answer:

a) There is a 2.28% probability that a new cup will overflow when filled by the automatic dispenser.

b) The mean amount dispensed by the machine should be set at 16.14 ounces to satisfy this wish.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Normal model with mean 16 ounces and standard deviation 0.31 ounces. This means that [tex]\mu = 16, \sigma = 0.31[/tex].

A new 16-ounce cup that is being considered for use actually holds 16.62 ounces of drink.

a. What is the probability that a new cup will overflow when filled by the automatic dispenser?

This probability is 1 subtracted by the pvalue of Z when [tex]X = 16.62[/tex]. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{16.62 - 16}{0.31}[/tex]

[tex]Z = 2[/tex]

[tex]Z = 2[/tex] has a pvalue of 0.9772. This means that there is a 1-0.9772 = 0.0228 = 2.28% probability that a new cup will overflow when filled by the automatic dispenser.

b. The company wishes to adjust the dispenser so that the probability that a new cup will overflow is .006. At what value should the mean amount dispensed by the machine be set to satisfy this wish?

This is the value of [tex]\mu[/tex], with [tex]X = 16.62[/tex] when Z has a pvalue of 0.94. It is between [tex]Z = 1.55[/tex] and [tex]Z = 1.56[/tex], so we use [tex]Z = 1.555[/tex].

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1.555 = \frac{16.62 - \mu}{0.31}[/tex]

[tex]\mu = 16.62 - 0.31*1.555[/tex]

[tex]\mu = 16.14[/tex]

The mean amount dispensed by the machine should be set at 16.14 ounces to satisfy this wish.

By using z-score formula we got that The probability that a new cup will overflow when filled by the automatic dispenser is 0.0228 and If probability that a new cup will overflow is .006 then value from which should the mean amount dispensed by the machine be set to satisfy this wish is 16.14

What is  z-score formula?

The Z-score measures how many standard deviations the measure is from the mean

[tex]Z=\frac{X-\mu}{\sigma}[/tex]

Given that

[tex]$\mu=16, \sigma=0.31$[/tex]

The probability that a new cup will overflow when filled by the automatic dispenser can be calculated as

[tex]$\begin{aligned}&Z=\frac{X-\mu}{\sigma} \\&Z=\frac{16.62-16}{0.31} \\&Z=2\end{aligned}$[/tex]

So by normal distribution table

[tex]P=$1-0.9772=0.0228$[/tex]

If probability that a new cup will overflow is .006 then value from which should the mean amount dispensed by the machine be set to satisfy this wish can be calculated as

[tex]$\begin{aligned}&Z=\frac{X-\mu}{\sigma} \\&1.555=\frac{16.62-\mu}{0.31} \\&\mu=16.62-0.31 * 1.555 \\&\mu=16.14\end{aligned}$[/tex]

By using z-score formula we got that The probability that a new cup will overflow when filled by the automatic dispenser is 0.0228 and If probability that a new cup will overflow is .006 then value from which should the mean amount dispensed by the machine be set to satisfy this wish is 16.14

To learn more about Z-score visit: https://brainly.com/question/25638875

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