Respuesta :
Answer : The correct option is (d) a solution of 0.10 M NaOH
Explanation :
(a) a solution of pH 3.0
First we have to calculate the pOH.
[tex]pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-3.0=11[/tex]
Now we have to calculate the [tex]OH^-[/tex] concentration.
[tex]pOH=-\log [OH^-][/tex]
[tex]11=-\log [OH^-][/tex]
[tex][OH^-]=1.0\times 10^{-11}M[/tex]
Thus, the [tex]OH^-[/tex] concentration is, [tex]1.0\times 10^{-11}M[/tex]
(b) a solution of 0.10 M [tex]NH_3[/tex]
As we know that 1 mole of [tex]NH_3[/tex] is a weak base. So, in a solution it will not dissociates completely.
So, the [tex]OH^-[/tex] concentration will be less than 0.10 M
(c) a solution with a pOH of 12.
We have to calculate the [tex]OH^-[/tex] concentration.
[tex]pOH=-\log [OH^-][/tex]
[tex]12=-\log [OH^-][/tex]
[tex][OH^-]=1.0\times 10^{-12}M[/tex]
Thus, the [tex]OH^-[/tex] concentration is, [tex]1.0\times 10^{-12}M[/tex]
(d) a solution of 0.10 M NaOH
As we know that [tex]NaOH[/tex] is a strong base. So, it dissociates to give [tex]Na^+[/tex] ion and [tex]OH^-[/tex] ion.
So, 0.10 M of [tex]NaOH[/tex] in a solution dissociates to give 0.10 M of [tex]Na^+[/tex] ion and 0.10 M of [tex]OH^-[/tex] ion.
Thus, the [tex]OH^-[/tex] concentration is, 0.10 M
(e) a [tex]1\times 10^{-4}M[/tex] solution of [tex]HNO_2[/tex]
As we know that 1 mole of [tex]HNO_2[/tex] in a solution dissociates to give 1 mole of [tex]H^+[/tex] ion and 1 mole of [tex]NO_2^-[/tex] ion.
So, [tex]1\times 10^{-4}M[/tex] of [tex]HNO_2[/tex] in a solution dissociates to give [tex]1\times 10^{-4}M[/tex] of [tex]H^+[/tex] ion and [tex]1\times 10^{-4}M[/tex] of [tex]NO_2^-[/tex] ion.
The concentration of [tex]H^+[/tex] ion is [tex]1\times 10^{-4}M[/tex]
First we have to calculate the pH.
[tex]pH=-\log [H^+][/tex]
[tex]pH=-\log (1.0\times 10^{-4})[/tex]
[tex]pH=4[/tex]
Now we have to calculate the pOH.
[tex]pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-4=10[/tex]
Now we have to calculate the [tex]OH^-[/tex] concentration.
[tex]pOH=-\log [OH^-][/tex]
[tex]10=-\log [OH^-][/tex]
[tex][OH^-]=1.0\times 10^{-10}M[/tex]
Thus, the [tex]OH^-[/tex] concentration is, [tex]1.0\times 10^{-10}M[/tex]
From this we conclude that, a solution of 0.10 M NaOH possess the greatest concentration of hydroxide ions.
Hence, the correct option is (d)