Answer:
0 lanes at full capacity
Explanation:
We have that 1 pixel = 3 bytes, we have 1920*1080 pixels, in order to find the number of bytes we do the product
[tex]1920*1080*3=6220800[/tex] B or [tex]6.221[/tex] MB.
We have that the monitor refreshes 60 times per second!, let's mutiply that number by 60
[tex]1920*1080*3*60=373248000[/tex] [B/second] or [tex]373.2[/tex] [MB/second].
Therefore, we are not using a single lane at its full capacity (500 MB/S), all the information could be carried out by a single lane