Answer:
The system has infinite number of solutions as both equations are equation of same line.
Step-by-step explanation:
Given equations:
A) [tex]-4x+6y=-20[/tex]
B) [tex]2x-3y=10[/tex]
Naming the first equation as A and 2nd as B.
Using elimination method to solve.
In order to eliminate [tex]x[/tex] we need to multiply such a number to equation B which when added to A eliminates [tex]x[/tex]
Multiplying equation B with 2.
[tex]2(2x-3y)=2\times 10[/tex]
[tex](2\times2x)-(2\times3y)=20[/tex] [Using distribution.]
[tex]4x-6y=20[/tex]
Now adding the above equation with A i.e [[tex]A+2B[/tex]]
(A) [tex]-4x+6y=-20[/tex]
+ (2B) [tex]4x-6y=20[/tex]
On adding we get [tex]0=0[/tex]
This means the system has infinite number of solutions as the two equations are equations of same line.
