The US Department of Transportation provides the number of miles that residents of the 75 largest metropolitan areas travel per day in a car. Suppose that for a simple random sample of 50 Buffalo residents the mean is 22.5 miles a day and the standard deviation is 8.4 miles a day. For an independent simple random sample of 40 Boston residents the mean is 18.6 miles a day and the standard deviation is 7.4 miles a day.a.What is the point estimate of the difference between the mean number of miles that Buffalo residents travel per day and the mean number of miles that Boston residents travel per day?b.What is the 95% confidence interval for the difference between the two population means?

Given that for a simple random sample of 50 Buffalo residents the mean is 22.5 miles a day and the standard deviation is 8.4 miles a day. For an independent simple random sample of 40 Boston residents the mean is 18.6 miles a day and the standard deviation is 7.4 miles a day

Group I Group II

Mean 22.5 18.6

STd dev 8.4 7.4

n 50 40

Mean difference =[tex]22.5-18.6=3.9[/tex]

a) point estimate for mean difference = 3.9

b) Std deviation pooled = 7.9723

pooled df = 88

Confidence interval 95% [tex]= (0.5864, 7.2136)[/tex]

williammosteller williammosteller · Answer 2 · 2021-03-08T17:46:30+01:00

williammosteller williammosteller

08-03-2021

Answer:

0.0665

Step-by-step explanation:

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