Question

Helicopter blades withstand tremendous stresses. In addition to supporting the weight of a helicopter, they are spun at rapid rates and experience large centripetal accelerations, especially at the tip. Calculate the centripetal acceleration at the tip of a 3.50 m long helicopter blade that rotates at 370 rev/min.

Answer 1

Answer:$5255.46 m/s^2$

Explanation:

Given

length of blade $L=3.5 m$

$N=370 rev/min$

Angular velocity $\omega =\frac{2\pi N}{60}$

$\omega =38.75 rad/s$

Centripetal acceleration is given

$a_c=\omega ^2\cdot L$

$a_c=38.75^2\cdot 3.5$

$a_c=5255.468 m/s^2$