Step-by-step explanation:
It is given that [tex]\frac{\textbf{width of computer monitor}}{\textbf{height of computer monitor}}=\frac{16}{9}[/tex]
It is given that [tex]\text{height of computer monitor}=13.5[/tex]
[tex]\text{width of computer monitor} =\text{height of computer monitor}\times \frac{16}{9}[/tex]
[tex]\text{width of computer monitor}=13.5\times \frac{16}{9} =\frac{216}{9} =24[/tex]
Hence the required width in inches is 24.