Ethyl acetate reacts with H2 in the presense of a catalyst to yield ethyl alcohol: C4 H8O2(l) +H2(g)-------> C2H6O6(l)



(a) Write a balanced equation for the reaction

(b) How many moles of ethyl alcohol are produced by reaction of 3.6 mol of ethyl acetate?

(c) How many grams of ethyl alcohol are produced by reaction 3.6 mol of ethyl acetate with H2?

(d) How many grams of ethyl alcohol are of ethyl alcohol are produced by reaction of 26.0 g of ethyl acetate with H2?

(e) How many grams of H2 are needed to react with 26.0 g of ethyl acetate?

Respuesta :

(a) C₄H₈O₂ (l) + 2 H₂ (g) → 2 C₂H₆O (l)

(b) 7.2 moles of ethyl alcohol

(c) 331.2 g of ethyl alcohol

(d) 27.14 g of ethyl alcohol

(e) 1.18 g of hydrogen

Explanation:

Ethyl acetate (C₄H₈O₂) is reacting with hydrogen (H₂), under the presence of a catalyst, to produce ethyl alcohol (C₂H₆O). You may find the chemical reaction in the attached picture.

(a) balanced chemical equation:

C₄H₈O₂ (l) + 2 H₂ (g) → 2 C₂H₆O (l)

(b) Knowing the chemical reaction, we devise the following reasoning:

if         1 mol of ethyl acetate will produce 2 moles of ethyl alcohol

then   3.6 moles of ethyl acetate will produce X moles of ethyl alcohol

X = (3.6 × 2) / 1 = 7.2 moles of ethyl alcohol

(c) number of moles = mass / molar weight

mass = number of moles × molar weight

mass of ethyl alcohol = 7.2 × 46 = 331.2 g

(d) number of moles = mass / molar weight

number of moles of ethyl acetate = 26 / 88 = 0.295 moles

Knowing the chemical reaction, we devise the following reasoning:

if         1 mol of ethyl acetate will produce 2 moles of ethyl alcohol

then   0.295 moles of ethyl acetate will produce Y moles of ethyl alcohol

Y = (0.295 × 2) / 1 = 0.59 moles of ethyl alcohol

mass = number of moles × molar weight

mass of ethyl alcohol = 0.59 × 46 = 27.14 g

(e) From point (d) we know that 26 g of ethyl acetate are equal to 0.295 moles of ethyl acetate.

Knowing the chemical reaction, we devise the following reasoning:

if         1 mol of ethyl acetate will react with 2 moles of hydrogen

then   0.295 moles of ethyl acetate will react with Z moles of hydrogen

Z = (0.295 × 2) / 1 = 0.59 moles of hydrogen

mass = number of moles × molar weight

mass of hydrogen = 0.59 × 2 = 1.18 g

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