Answer:
23.66°C
Explanation:
We are given;
- Mass of Pb as 20.0 g
- Amount of heat transferred is 4950 Joules
- Mass of water is 50.0 g
We are required to calculate the temperature change
- Note that the quantity of heat, Q absorbed is given by;
Q =mass × specific heat capacity × Change in temperature
In this case;
Specific heat capacity, c of water = 4.184 J/g°C
But, Q = mcΔT
Amount of heat absorbed by water is 4950 J
Rearranging the formula;
ΔT = Q ÷ mc
= 4950 J ÷ (50.0 g × 4.184 J/g°C)
= 23.66°C
Thus, the temperature of water will change by 23.66°C
