Answer:
0.5504
Explanation:
We can use Bay's theorem to solve this question
P( No physics career/fail) = P(No Physics career and fail)/P(Fail)
= P( Fail/ No physics career)×P( no physics career)/P( fail)
=[tex]\frac{0.3\times1}{(0.7\times0.35)+(0.3\times1)}[/tex]
=0.5504