Answer:
The volume of the rectangular block of mass 600 g is 150 cm³.
Explanation:
Given:
Mass of the block is, [tex]m=600\ g[/tex]
Length of the block is, [tex]l=25\ cm[/tex]
Width of the block is, [tex]b=2\ cm[/tex]
Height of the block is, [tex]h=3\ cm[/tex]
Volume of a rectangular block is given as:
[tex]V=l\times b\times h[/tex]
Now, plug in 25 for [tex]l[/tex], 2 for [tex]b[/tex], 3 for[tex]h[/tex] and solve for volume, [tex]V[/tex]. This gives,
[tex]V=25\times 2\times 3\\V=150\ cm^3[/tex]
The volume of the rectangular block of mass 600 g is 150 cm³.
Density can also be determined and is given as:
[tex]Density=\frac{\textrm{mass}}{\textrm{volume}}=\frac{600}{150}=4\ g/cm^3[/tex]
Density is 4 g/cm³.
The density of the rectangular block is 4 [tex]g/cm^3[/tex].
Given the following data:
In this exercise, you're required to solve for the density of the rectangular block.
First of all, we would determine the volume of the rectangular block by using the following formula;
[tex]Volume = length[/tex] × [tex]width[/tex] × [tex]height[/tex]
[tex]Volume = 25[/tex] × [tex]2[/tex] × [tex]3[/tex]
Volume of rectangular block = 150 [tex]cm^3[/tex]
Now, we can solve for the density of the rectangular block using the formula;
[tex]Density = \frac{Mass}{Volume}[/tex]
Substituting the values into the formula, we have;
[tex]Density = \frac{600}{150}[/tex]
Density = 4 [tex]g/cm^3[/tex]
Therefore, the density of the rectangular block is 4 [tex]g/cm^3[/tex].
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