Answer:
The average cost of each tape is [tex]\frac{45}{v}[/tex]
Step-by-step explanation:
Total number of tapes bought = v tapes
Total cost paid for v tapes = $45
By UNITARY METHOD:
If the cost of n objects is A.
Then the unit price is [tex]\frac{\textrm{Total cost of n objects}}{\textrm{Number of the objects}}[/tex]
Cost of v tapes = $45
⇒ Cost of 1 tape = [tex]\frac{\textrm{Total cost of v tapes}}{\textrm{v}}[/tex]
=[tex]\frac{45}{v}[/tex]
Hence, the average cost of each tape is [tex]\frac{45}{v}[/tex]
