Answer: [tex]7.21kJ/^0C[/tex]
Explanation:
Total heat released during reaction is equal to total heat gained by water and bomb calorimeter.
Let the heat released during reaction be q.
q = -16.0 kJ
Thus heat absorbed by calorimeter = + 16.0 kJ
[tex]q_{cal}=c_{cal}\times \Delta T[/tex]
[tex]q_{cal}[/tex] = Heat gained by calorimeter = 16000 J
[tex]c_{cal}[/tex] = Heat capacity of calorimeter = ?
Change in temperature = ΔT = 2.22°C
[tex]16000J=c_{cal}\times 2.22^0C[/tex]
[tex]16000J=c_{cal}\times 2.22^0C[/tex]
[tex]c_{cal}=\frac{16.0J}{2.22^0C}=7.21kJ/^0C[/tex]
Thus heat capacity of a calorimeter is [tex]7.21kJ/^0C[/tex]