Respuesta :
Answer:
1.34×10²³ molecules
Explanation:
Given data:
Volume of container = 5 L
Number of molecules of ammonia = 2.00×10²³
Number of molecules of Ar = ?
Volume of container = 5 L
Temperature = 273 K
Pressure = 1 atm
Solution:
PV = nRT
n = PV/RT
n = 1 atm. 5 L / 0.0821 atm. L. mol⁻¹. K⁻¹ . 273.15 K
n = 5 L.atm /22.426 atm. L. mol⁻¹.
n = 0.223 mol
Number of molecules of argon:
One mole = 6.02 ×10²³ molecules
0.223 mol
6.02 ×10²³×0.223
1.34×10²³ molecules