Question

Where is the hole for the following function located?
f (x) = StartFraction x + 3 Over (x minus 4) (x + 3) EndFraction
answer choices ->

x = –3
y = –3
x = 3
y = 3

Answer 1

At x = -3 is located a hole.

Explanation:

In this problem, we have the following function:

$f(x)=\frac{x+3}{(x-4)(x+3)}$

A hole will lie at the x-values that makes the function undefined, that is, when the denominator is zero. In a mathematical language:

$(x-4)(x+3)=0$

From this equation, we get two solutions:

$x=4 \\ \\ x=-3$

At those x-values the function will have a hole. From the choices:

At x = -3 is located a hole.

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Derivative: https://brainly.com/question/13419010

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Answer 2

Answer:

At x = -3 is located a hole. At x = -3 is located a hole. At x = -3 is located a hole. At x = -3 is located a hole. At x = -3 is located a hole. At x = -3 is located a hole. At x = -3 is located a hole. At x = -3 is located a hole. At x = -3 is located a hole.

Step-by-step explanation: