The inspector can expect to find 450 units in a batch of 3000 phones
Step-by-step explanation:
Given
Total Cellular Phones = S = 60
Defective phones = E = 9
We will calculate the probability of defective forms first
So,
[tex]P(d)=\frac{E}{S}\\=\frac{9}{60}\\=0.15[/tex]
The probability of defective phones in 60 phones is 0.15
Now,
Total phones = 3000
[tex]P(d)=0.15*3000\\=450[/tex]
The inspector can expect to find 450 units in a batch of 3000 phones
Keywords: Probability, Experimental probability
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