Answer:
3x - y + 5 = 0
Step-by-step explanation:
When two points are given and the equation of the line passing through those points are asked we use two - point form to determine the equation of the line.
Two - point form: [tex]$ \frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 -x_1} $[/tex]
Here the two points are: (2,11) & (-8,-19).
Let [tex]$ (x_1,y_1) = (2,11) $[/tex] and [tex]$ (x_2, y_2) = (-8,-19) $[/tex]
Substituting in the formula we have:
[tex]$ \frac{y - 11}{-19 - 11} = \frac{x - 2}{-8 - 2} $[/tex]
[tex]$ \implies \frac{y - 11}{-30} = \frac{x - 2}{-10} $[/tex]
Simplifying we get:
y - 11 = 3x - 6
⇒ 3x - y + 5 = 0
