Answer:
c=0
Step-by-step explanation:
*graphed*
coordinates are 0,0 6,8 0,12 10,0
*plug them into c=x+y*
C=0+0=0
C=6+8=14
C=0+12=12
C=10+0=10
since 0 is the smallest value C=o and if they want a fr number then your second option is C=10
Answer:
C = 0 is the minimum value
Step-by-step explanation:
Sketch
2x + y = 20
with x- intercept = (10, 0) and y- intercept = (0, 20)
2x + 3y = 36
with x- intercept = (18, 0) and y- intercept = (0, 12)
Solve 2x + y = 20 and 2x + 3y = 36 to find intercept at (6, 8)
The feasible region has vertices at
(0, 20), (12, 0) and (6, 8)
Evaluate the objective function C = x + y at each vertex
(0, 20) → C = 0 + 20 = 20
(12, 0) → C = 12 + 0 = 12 ← minimum value
(6, 8) → C = 6 + 8 = 14
The minimum value is C = 12 when x = 12 and y = 0
