Question

n a Gallop poll of 1012 randomly selected adults, 9% said that cloning of humans should be allowed. We are going to use a .05 significance level to test the claim that less than 10% of all adults say that cloning of humans should be allowed. The test statistic for this test is -1.06. What is the p-value for this test statistic?

Answer 1

Answer:0.1446

Step-by-step explanation:

Let p be the population proportion of adults say that cloning of humans should be allowed.

As per given , the appropriate set of hypothesis would be :-

$H_0: p\geq0.10\\\\ H_a: p<0.10$

Since $H_a$ is left-tailed and sample size is large(n=1012) , so we perform left-tailed z-test.

Given : The test statistic for this test is -1.06.

P-value for left tailed test,

P(z<-1.06)=1-P(z<1.06)        [∵P(Z<-z)=1-P(Z<z]

=$1-0.8554=0.1446$          (Using z-value table.)

Hence, the p-value for this test statistic= 0.1446