The acceleration is [tex]2.5 m/s^2[/tex]
Explanation:
This is a uniformly accelerated motion (constant acceleration), therefore we can apply the following suvat equation:
[tex]v=u+at[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
For the scooter in this problem, we have
u = 0 (it starts from rest)
v = 10.0 m/s is the final velocity
t = 4.0 s is the time interval
Solving for a, we find the acceleration:
[tex]a=\frac{v-u}{t}=\frac{10-0}{4}=2.5 m/s^2[/tex]
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