Question

The Mariana trench is located in the Pacific Ocean at a depth of about 11 000 m below the surface of the water. The density of seawater is 1025 kg/m3. (a) If an underwater vehicle were to explore such a depth, what force would the water exert on the vehicle's observation window (radius = 0.184 m)? (b) For comparison, determine the weight of a jetliner whose mass is 3.96 × 105 kg.

Answer 1

Answer:

a. $F=11.7416x10^6 N$

b. $W=3.8808x10^6N$

Explanation:

Pressure is find by:

$P=P_{out}-P_{in}$

$P_{in}=101325 N/m^2$

$P_{out}=p*g*d=1025 kg/m^3*9.8m/s^2*11000m$

$P_{out}=1.10495x10^8 N/m^2$

$P=(1.10495x10^8 -0.101325x10^6)N/m^2$

$P=110.3936x10^6 N/m^2$

a.

$F=P*A$

$A=\pi*r^2=\pi*(0.184m)^2=0.106m^2$

$F=110.3936x10^6 N/m^2*0.106m^2$

$F=11.7416x10^6 N$

b.

$W=m*g$

$W=3.96x10^5kg*9.8 m/s^2$

$W=3.8808x10^6N$