Question

Ammonia (NH3) can be produced by the reaction of hydrogen gas with nitrogen gas:

3H2 + N2→2NH3

A chemist reacts 2.00 mol H2 with excess N2 . The reaction yields 0.80 mol NH3 .

What is the percent yield of the reaction? A. 25% B.40% C.60% D.80%

Answer 1

Answer:

Percent yield = 61.5%

Explanation:

Given data:

Moles of hydrogen = 2.00 mol

Actual yield of ammonia= 0.80 mol

Percent yield = ?

Solution:

Chemical equation:

3H₂ + N₂ → 2NH₃

Now we will compare the moles of ammonia with hydrogen from balance chemical equation:

                     H₂       :       NH₃

                      3        :         2

                      2        :       2/3×2 = 1.3 mol

Percent yield:

Percent yield = Actual yield / theoretical yield × 100

Percent yield = 0.80 mol /1.3 mol × 100

Percent yield = 0.615 × 100

Percent yield = 61.5%

Answer 2

Answer:

40%

Explanation:

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