Question

A hypothetical population of 10,000 humans in a designated geographical location. In the population, 6,840 individuals have blood type AA, 2,860 have blood type AB, while 300 individuals have blood type BB. a. What is the frequency of each genotype? b. What are the allele frequencies? c. Is the population in Hardy Weinberg? Which selection mechanism is acting on the population?

Answer 1

Answer:

a)

AA - 0.684

AB -0.286

BB - 0.03

b)

A - 0.827

B - 0.173

c) Yes

d) No , selection mechanism

Explanation:

Given -

Total population $= 10000$

Population with AA blood type $= 6840$

Population with AB blood type $= 2860$

Population with BB blood type $= 300$

Frequency of AA genotype $= \frac{6840}{10000\\ = 0.684$

Frequency of AB genotype $= \frac{2860}{10000\\ = 0.286$

Frequency of AA genotype $= \frac{300}{10000\\ = 0.03$

Allele frequency of A is equal to

$\sqrt{0.684} \\= 0.827$

Allele frequency of B is equal to

$\sqrt{0.03} \\= 0.173$

For being in Hardy Weinberg equilibrium

Sum of frequency of allele A and allele B is equal to 1

$0.827 + 0.173\\= 1$

Since the population is in Hardy Weinberg's equilibrium, no selection mechanism is acting