Question

The voltage and the current in the primary coil of a nonideal transformer are 120 volts and 2.0 amperes. The voltage and the current in the secondary coil are 19.4 volts and 11.8 amperes. What is the efficiency e of the transformer? The efficiency of a transformer is defined as the ratio of the output power to the input power, expressed as a percentage: e=100Pout/Pin.

Answer 1

Answer:

95.38 %

Explanation:

Transformer is an electrical device which has two or more coils of wire used to transfer electrical energy by changing magnetic field

Power of a transformer coil = voltage * Current

Transformer does not require any moving parts to transfer energy. Therefore we cannot see any friction or windage losses here. But they have some types of losses called “copper losses” and “iron losses” but generally these are quite small.

So there for it can affect the efficiency of the transformer also. Efficiency can be defined as follow

$efficiency=\frac{P_(out)}{P_(in)}*100 \\=\frac{V_(secondary)*I_(secondary)}{V_(primary)*V_(primary)} *100\\=\frac{19.4*11.8}{120*2} *100\\=95.38 %$